Warriors’ Andre Iguodala earns NBA all-defensive first-team honors 

click to enlarge Forward Andre Iguodala, left, is the first Warriors player to be named first-team NBA all-defensive team since 1971. - BEN MARGOT/2013 AP FILE PHOTO
  • Ben Margot/2013 AP file photo
  • Forward Andre Iguodala, left, is the first Warriors player to be named first-team NBA all-defensive team since 1971.

Warriors forward Andre Iguodala beat out Miami Heat star LeBron James for a spot on the NBA's all-defensive first team, the league announced Monday.

Iguodala is the first Warrior on the all-defensive first team since Nate Thurmond was in 1970-71. Ex-Warriors Latrell Sprewell was named to the second team in 1993-94.

The Chicago Bulls' Joakim Noah and Indiana Pacers' Paul George received the most votes, while Los Angeles Clippers guard Chris Paul and Oklahoma City Thunder forward Serge Ibaka round out the team.

James and defensive player of the year runner-up Roy Hibbert were both on the second team.

Iguodala averaged 1.5 steals as the Warriors jumped from No. 19 in defense in 2012-13 to 10th this season. James and Iguodala each received

57 first-team votes, but Iguodala had 14 more second-team votes to edge out James for the final spot on the first team.

In his first season with the Warriors, the 6-foot-6 Iguodala led the NBA in plus-minus per game, averaging a +9.0 differential while on the court. He also tied for eighth in the league with a defensive rating of 96.9 (among qualified players who logged at least 20 minutes per game).

Iguodala was previously named to the all-defensive second team as a member of the Philadelphia 76ers in 2010-11.

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